((x+1)^(1/2))-2x=2

Solution for ((x+1)^(1/2))-2x=2 equation:

((x+1)^(1/2))-2x=2

We move all terms to the left:

((x+1)^(1/2))-2x-(2)=0

We add all the numbers together, and all the variables

((x+1)^(+1/2))-2x-2=0

We add all the numbers together, and all the variables

-2x+((x+1)^(+1/2))-2=0

We multiply all the terms by the denominator


-2x*2))+((x+1+1)^(-2*2))=0

We add all the numbers together, and all the variables

-2x*2))+((x+2)^(-4))=0

We add all the numbers together, and all the variables

-2x*2))+((x=0

Wy multiply elements

-4x^2=0

a = -4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-4)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-8}=0$